学RPG制作大师？关注一个公众号就够了。 RPG制作大师基础教程，持续更新中... RPG制作大师基础教程 引用自 author：人本游戏，地丑德齐，天道酬勤 索引【RPG制作大师基础教程】 工具入门篇：创建一个世界 工具入门篇：新建一个地图 工具入门篇：绘制一个房子(外观) 工具入门篇：绘制一个房子(内部) 工具入门篇：Hello,NPC!工具入门篇：造一个任意门 事件基础篇 事件基础篇：什么是开关 事件基础篇：什么是变量 事件基础篇：什么是条件分歧 事件基础篇：什么是循环 事件基础篇：出现条件与触发方式 事件基础篇：显示图片怎么玩 事件基础篇：控制字符怎么用 事件进阶篇 事件进阶篇：昼夜系统 事件进阶篇：踩冰小游戏 事件进阶篇：点灯游戏 事件进阶篇：脚步声 事件进阶篇：限时武器 事件进阶篇：开场剧情 数据库篇 数据库篇：特性与效果 地图绘制篇 地图绘制篇：【用RTP绘制地图】民宅 地图绘制篇：【用RTP绘制地图】商店 地图绘制篇：【用RTP绘制地图】树林 地图绘制篇：【用RTP绘制地图】TileA地图绘制篇：【使用RTP绘制地图】比例 地图绘制篇：【使用RTP绘制地图】阴影 资源整理篇 资源整理篇：如何导入素材 资源整理篇：将自己喜欢的素材放入游戏 资源整理篇：行走图修改 资源整理篇：图标修改和制作 资源整理篇：图块修改 资源整理篇：制作一个LOGO 资源整理篇：世界地图的制作 资源整理篇：摇摆的树 资源整理篇：立绘与行走图的配合 资源整理篇：使用远景来画地图吧！ 资源整理篇：简易的LOGO制作教程 开源游戏篇 开源游戏篇：我是跳跳侠 开源游戏篇：沉默的纸飞机 开源游戏篇：逐梦 游戏设计篇 游戏设计篇：数还是诗？——游戏浪漫主义的取舍 游戏设计篇：设计一个火球术：LV2——异形的策划探索之旅（95） 游戏设计篇：怎样写好一篇游戏评测？ 游戏设计篇：一句话灵感 游戏设计篇：角色设定法则：我不是拯救世界，我是拯救你！ 游戏设计篇：如果宝箱NPC拟人化……你会如何理解这个角色。 游戏设计篇：随便聊聊，我的RPG观（长，慎入） 绘画作品欣赏 《雨天的房间》制作思路及全过程

作为独立游戏开发者，脱发常常是个大问题，因此这份指南应运而生。 1. **作息调整**：日常生活中应养成早睡早起的习惯，保证充足睡眠，避免熬夜（尽管这几乎不可能），以此预防脱发。 2. **饮食调理**：多食用补气血的食物，如阿胶、红枣等；同时增加黑芝麻、黑豆等富含黑色素的食物摄入，帮助预防脱发。 3. **缓解精神压力**：平时可多听舒缓音乐，多参与户外运动，从而舒缓内心压力，减少神经衰弱，预防脱发等问题。 4. **头部护理**：每晚睡前可适当按摩头部或梳头，促进头部血液循环。5. 补充铁质。经常脱发的人常缺铁。铁质丰富的食物有黄豆、黑豆、蛋类、带鱼、虾、熟花生、菠菜、鲤鱼、香蕉、胡萝卜、马铃薯等。 6. 补充植物蛋白。头发干枯、发梢裂开，可多吃大豆、黑芝麻、玉米等。 7. 多吃含碱性物质的新鲜蔬菜和水果。脱发及头发变黄的因素之一是血液中存在酸性毒素，这通常是由于体力和精神过度疲劳，或长期过食纯糖类和脂肪类食物，导致体内代谢过程中产生酸毒素。肝类、肉类、洋葱等食品中的酸性物质容易使血中酸毒素过多，因此要少吃。 8. 补充碘质。头发的光泽与甲状腺的作用有关，补碘能增强甲状腺的分泌功能，有利于头发健美。可多吃海带、紫菜、牡蛎等食品。 9.补充维生素E。维生素E可抵抗毛发衰老，促进细胞分裂，使毛发生长。可多吃鲜莴苣、卷心菜、黑芝麻等。 10. 避免暴晒。日光中的紫外线会对头发造成损害，使头发干枯变黄，因此夏季要避免日光暴晒，在室外、日光浴时要注意防护。 11. 远离烟草。吸烟已被认为是引起脱发的危险因素之一。脱发高危家庭应注意尽量让子女远离烟草。 12. 减少染发烫发。经常染发、烫发会使头发失去光泽和弹性，甚至变黄变枯。染发、烫发间隔时间至少要3-6个月。 枸杞黑芝麻粥： 黑芝麻30克、大米80克、糯米20克、枸杞10克、糖桂花1勺，冰糖1勺。所有材料洗净，枸杞泡软，糯米需提前浸泡2小时。### 粳米黑芝麻粥： 黑芝麻30克，粳米100克。将黑芝麻捣碎，粳米淘净，放入锅中，加水300克，用小火煮至汤汁稠浓成粥即成。具有滋补肝肾、养血填精的作用。 ### 大米黑芝麻粥： 黑芝麻25克，大米适量。将黑芝麻捣碎，大米淘净，加水适量煮粥。每日分2～3次食用。此粥能补肝肾、润五脏，适用于产后乳汁不足、消瘦、便秘、须发早白等情况。 ### 燕麦黑芝麻粥： 材料：大米、燕麦、黑芝麻、白糖各适量。 做法：燕麦用水泡开备用。将水煮开后，放入大米、糯米和黑芝麻，用小火将粥煮得黏糯，然后加入冰糖和枸杞再煮约15分钟。食用时浇上一勺糖桂花即可。将大米和黑芝麻煮成粥，出锅前放入燕麦，再煮5分钟，放入适量白糖拌匀即可。 山药黑芝麻粥： 所需材料：大米、山药、黑芝麻、梨汁、冰糖各适量。 制作步骤： 1. 大米淘洗干净； 2. 山药清洗干净，戴上手套刮掉外皮，切成滚刀小块； 3. 将大米、山药和黑芝麻一起装入高压锅，加入足量的水，再加入两大块梨汁冰糖，盖好盖子； 4. 大火烧至上汽后，转小火煮10分钟即可。 简单黑芝麻粥： 制作步骤： 1. 平时先把黑芝麻炒熟，研成细末备用； 2. 等米粥煮熟后，加入准备好的黑芝麻末再煮5分钟左右即可（一般100克米中加50克黑芝麻）。补充：如果有搅拌机，可先将黑芝麻搅打成粉末再煮，味道会更香糯；煮粥时防止糊锅底、溢出的办法是，在水沸腾后再下米，并在煮锅里放一只陶瓷勺，就可以轻松解决了。

Did you have the idea of adding labyrinths to your game? Labyrinths are a fun way to keep the player engaged, however they may prove to be too much work. If you wanted to make two 3x3 labyrinths you would need 18 maps! Well, look no further. My mechanics can create random 3x3 labyrinths automatically using only two maps! The labyrinth will be generated as soon as the player enters it, and will remain consistent until the player solves it or forfeits it! Next time they will enter it, they will come across a brand new labyrinth with a different solution than the previous one! Introduction In this guide we will make a "machine" that generates randomized labyrinths that though remain consistent until the player either solves them or forfeits them. For this example we will always assume: -all labyrinths will have a total of 9 rooms. (VroomTotal=9) -all labyrinths will have the shape of a box. (VroomShape=1) -the entrance is from the bottom of the box, into room 2. (Ventrance=2) -the exit is towards the top of the box, out of room 8. (Vexit=8) -the solution only needs you to traverse the labyrinth and find the exit, without needing to find any items or press any buttons In order to better follow the logic draw a box of 9 squares on a paper and number them from 1 to 9, from bottom left to top right, so that room 4 is above room 1, etc. This way you will not get lost, especially in bigger labyrinths. Note: Once you create this example in your game, you can play around with different shapes, entrances and exits. Everything is randomizable! 1. Sample Room Create a simple square room with 4 exits: LEFT, RIGHT, UP, DOWN. Name it "Sample Room". This room will be our reference. This example will only use this room, but when you enhance your labyrinths you can use this as an example. Don't make it complicated, don't add columns and stuff like that. Just a simple room. This is the only room we need, however we will also make another one for simplicity's sake. Create a parallel event in "Sample Room". This parallel event will have inside it a Common Event called "Rules", a "FadeIn" command and the "Erase Event" command. 2. Transitional Map Create an empty map, without anything inside. Name it "Transitional". This room will be used only to ensure any parallel events in our Sample Room are restarted. When you become proficient with creating labyrinth machines, you will be able to bypass this room entirely, but for now we will need it. Create a parallel event in "Transitional". This parallel event will have inside it a "Transfer Player" command, with our "Sample Room" as a map, and variables (VposX) and (VposY) as the coordinates. 3. Common Event "Creation" Create a Common Event called "Creation". This will be called only ONCE per labyrinth, just before the player gets transfered inside the labyrinth. So, for example, as the player agrees to enter the labyrinth, the Common Event "Creation" will be called before the "Transfer Player" command. Inside this event, put the variables we discussed in the introduction: VroomTotal=9 VroomShape=1 Ventrance=2 Vexit=8 4. First Variables and Switches So, forget about the "Creation" for now, we will come back to it whenever we want to add something to it. Now we have to make our first rules. For these we will need: -Variable that holds the room we are currently in (VroomCurrent) -Variable that tells the game the room we are heading towards (VroomTo) -Switch that blocks the left exit (Switch LEFT) -Switch that blocks the bottom exit (Switch DOWN) -Switch that blocks the right exit (Switch RIGHT) -Switch that blocks the top exit (Switch UP) Before we do anything else, we already know where the player currently is in the beginning of the labyrinth. They are at the entrance, right? Let's pop this in "Creation" - it needs to be after Ventrance has been initialized. VroomCurrent=Ventrance 5. Directional Switches and Events Now, first of, let's put the switches into place. Create an event for each one of the exits. Each of these four events must be: -Trigger: Player Touch -Below Characters -Create 2nd page -Trigger: Action -Same as Characters -Image: a boulder or a door or something that blocks movement -Condition: Switch: one of the four directional switches we made, depending on where this exit is For example the left exit's 2nd page needs the switch "LEFT" as a condition. These 2nd pages will be activated when the exit is blocked. Later on we will see more of that. Remember that static images also need "direction fix" to be ticked, so that they don't change shape when the character presses the action button on them. Now, remember i told you to draw the box on a paper? Four things immediately come from that. -Each room to the left is one number lower than the current room's number -Each room to the right is one number higher than the current room's number -Each room to the bottom is three numbers lower than the current room's number -Each room to the top is three numbers higher than the current room's number Now back to our exit events. So far we kept the first page blank since we didn't have any rules. However now we have our first most basic rules. These are just directional so we won't put them inside the Common Event "Rules". Instead, we will put them right on the exits. When the player touches them, our machine needs to realize that the player is changing rooms, and where exactly is the player going. So. -Left exit needs VroomTo=VroomCurrent VroomTo-=1 VposX=i VposY=j FadeOut Transfer Player to Transitional - wherever "i" and "j" will need to be fine-tuned depending on the rooms you will be using. They are meant to give a sense of continuity to our labyrinth. In this room, they are the coordinates of the square in front of the right exit - since we are going left, we are entering the room from the right. All other exits need the same things. The differences are the VroomTo subtraction or addition as well as the i and j values. So copy and paste these commands to all first pages of all directional events and change the VroomTo to: -Right exit: VroomTo+=1 -Top exit: VroomTo+=3 -Bottom exit: VroomTo-=3 Now, we need a way to tell the machine that the room that the player will go to, is the room that the player is arriving in. This is why we have the Transitional map. Let's go there and add this to its parallel event, before the Transfer Player command: VroomCurrent=VroomTo Now, when the player transitions, they will be transferred to the room they were heading towards. 6. Take a deep breath. First rules. The first rule is always DON'T PANIC. That was a lot wasn't it? Don't worry, we still have a ton to go through. At least we have now created a way to traverse the rooms while keeping track of where the player is inside the box! But right now it's not that much of a box, right? Let's fix that. And with this, we begin writing our first rules: Physical Limitations. Let's go to our Common Event called "Rules". Before we do anything, we need to make sure that no switches will remain on or off from previous rooms, so let's begin with a comment "RESET" and add our reset: switches LEFT,RIGHT,DOWN,UP =false Add a comment called "Physical Limitations" and let's begin creating our box. The physical limitations of a box are that you cannot exit its sides and corners. You can only exit through the entrance, forfeiting the labyrinth, and the exit, solving the labyrinth. See your paper? Now you can clearly see which directions must always be blocked, no matter how the labyrinth ends up like. So. Let's do this: -Corners If VroomCurrent=1, switches LEFT,DOWN =true (bottom left corner) If VroomCurrent=3, switches RIGHT,DOWN =true (bottom right corner) If VroomCurrent=7, switches LEFT,UP =true (top left corner) If VroomCurrent=9, switches RIGHT,UP =true (top right corner) -Sides If VroomCurrent=2, switch DOWN =true (bottom side) If VroomCurrent=4, switch LEFT =true (left side) If VroomCurrent=6, switch RIGHT =true (right side) If VroomCurrent=8, switch UP =true (top side) We also need to make sure the entrance and exit are definitely unblocked. Let's add those: If VroomCurrent=Ventrance, switch DOWN =false If VroomCurrent=Vexit, switch UP =false Note that these two need to be positioned at the very end of our rules, since we block every entrance and exit there. The reason i do this in this manner is because it will help you if you want to add further code afterwards to randomize entrances and exits. I am also assuming that every entrance is downwards and every exit is upwards. These are obviously all randomizable, but for this example i will keep things simple. 7. Exit the box We are now at a point that we have a proper box. The player cannot leave the box but from the entrance or exit. Since we now know this, let's add it in our Transitional Map. We need to make a small adjustment now. This is quite crucial so stay with me. Remember that we always transfer the player back into the labyrinth? Now we need to add some conditions for that first. Our conditions are: -Has the player exited the labyrinth through the exit? -Has the player exited the labyrinth through the entrance? The rest of the code will be cut and pasted so let's begin: If VroomCurrent=Ventrance, transfer player to (map of the entrance of the labyrinth) - The player has exited through the entrance ELSE If VroomCurrent=Vexit, transfer player to (map of the exit of the labyrinth) - The player has exited through the exit ELSE (the player hasn't exited the labyrinth so in here we will cut and paste the rest of the code) VroomCurrent=VroomTo Transfer player to (Sample Room, VposX, VposY) We've done it! Now we have a box with an entrance and an exit. Each room is connected and our machine knows exactly where the player is. This "super" map, built of 9 maps, built out of a single map, is our area where our labyrinth will be built. 8. Building the labyrinth - First steps The first thing a labyrinth needs, in my humble opinion, is that its solution must never be a straight line from the entrance to the exit. In this example our entrance is room 2 and our exit is room 8. This means that room 5 must have at least one exit blocked, out of the ones leading to the exit or the entrance. In this example these exits are its top and bottom ones. Since we want this to be random, let's do so. Go to our "Creation" and add another variable: VmiddleBlock=1..2 Now we have a random variable that will indicate which one of these is permanently blocked. Let's say that 1 means the bottom exit and 2 means the top one. Let's add this to our rules. Go to "Rules" and add: If VroomCurrent=5 AND VmiddleBlock=1, switch DOWN =true If VroomCurrent=5 AND VmiddleBlock=2, switch UP =true If you test it, you will see that once you are in room 5, in the middle of the box, you will have one of the two exits blocked. However, right now, we only have the blocks exiting room 5, but not the ones entering it. Let's make this happen! If VroomCurrent=2 AND VmiddleBlock=1, switch UP =true If VroomCurrent=8 AND VmiddleBlock=2, switch DOWN =true Now it starts gaining continuity. Now you are starting to feel like you are indeed inside a box, and it might even begin resembling something of a labyrinth. However, a labyrinth is supposed to have only one solution. Did you ever solve labyrinths on paper? The "cheating" way was to solve them starting from the exit. So this is what we're going to do in order to create our solution. We need to make sure that only one path is valid, starting from the exit. 9. Creating a solution - Top So, starting at the exit, we are found in room 8. This room has three exits, RIGHT, DOWN and LEFT. So let's add a random variable to randomize which one of these exits is part of the labyrinth's solution. Let's go to our "Creation" and add: VtopSol=1..3 Let's say that 1 means LEFT, 2 means RIGHT and 3 means DOWN. Now we are at a pickle, since the correct solution might be DOWN but our VmiddleBlock might be 2, blocking our way. Let's make sure this doesn't happen by transforming our code: Loop VtopSol=1..3 If VtopSol<3, Break Loop ELSE If VmiddleBlock!=2, Break Loop Note three things here. First, "!=" means "not equal to". Second, once a Loop hits the Break Loop command it will stop whatever it's doing and continue reading whatever there is after the loop. Third, if it doesn't encounter the Break Loop command, it will go back up and repeat the loop from the first command. This means that if VtopSol=3 and VmiddleBlock=2 the Loop will just repeat. Ok, so now we have a single solution starting from the exit. Let's go add it to our Rules. If VroomCurrent=8 AND VtopSol=1, switches RIGHT,DOWN =true If VroomCurrent=8 AND VtopSol=2, switches LEFT,DOWN =true If VroomCurrent=8 AND VtopSol=3, switches LEFT,RIGHT =true Now we also need to add these to our adjacent rooms. Continue adding them to our Rules. If VroomCurrent=9 AND VtopSol=1, switch LEFT =true If VroomCurrent=9 AND VtopSol=3, switch LEFT =true If VroomCurrent=7 AND VtopSol=2, switch RIGHT =true If VroomCurrent=7 AND VtopSol=3, switch RIGHT =true If VroomCurrent=5 AND VtopSol=1, switch UP =true If VroomCurrent=5 AND VtopSol=2, switch UP =true 10. Creating a solution - Middle Now we must continue in a similar manner, going downwards towards the entrance. If you have your paper handy, you will see that we are now either in room 7, 9 or 5. However, if we are in room 5, the path downwards is definitely blocked. We need to keep this in mind in our next step. So if we are in rooms 7 or 9, we can only go downwards. If we are in room 5, we are already in the middle of the labyrinth. So we are now either in room 4,5 or 6. Remember that we said that if we are in room 5, the path downwards is definitely blocked. This means that no matter which room we are in, we only have 2 directions to go, and only 1 of these is correct. So back to our "Creation". Add: VmiddleSol=1..2 This will work along with VtopSol's value, so that we know which room we were in. Remember: When VtopSol=1 it means that we are in room 4 now. When VtopSol=2 it means that we are in room 6. When VtopSol=3 it means that we are in room 5 with the bottom exit blocked from VmiddleBlock. So let's go to our Rules and add: If VroomCurrent=4 AND VmiddleSol=1 AND VtopSol=1, switch DOWN =true If VroomCurrent=4 AND VmiddleSol=2 AND VtopSol=1, switch RIGHT =true If VroomCurrent=6 AND VmiddleSol=1 AND VtopSol=2, switch DOWN =true If VroomCurrent=6 AND VmiddleSol=2 AND VtopSol=2, switch LEFT =true If VroomCurrent=5 AND VmiddleSol=1 AND VtopSol=3, switch LEFT =true If VroomCurrent=5 AND VmiddleSol=2 AND VtopSol=3, switch RIGHT =true And let's add the same rules for the adjacent rooms: If VroomCurrent=1 AND VmiddleSol=1 AND VtopSol=1, switch UP =true If VroomCurrent=5 AND VmiddleSol=2 AND VtopSol=1, switch LEFT =true If VroomCurrent=3 AND VmiddleSol=1 AND VtopSol=2, switch UP =true If VroomCurrent=5 AND VmiddleSol=2 AND VtopSol=2, switch RIGHT =true If VroomCurrent=4 AND VmiddleSol=1 AND VtopSol=3, switch RIGHT =true If VroomCurrent=6 AND VmiddleSol=2 AND VtopSol=3, switch LEFT =true 11. Creating a solution - Bot Note that if VtopSol is 1 or 2 (we are in room 4 or 6), VmiddleSol is 1 (unable to go downwards) and VmiddleBlock is 2, then there are still 2 solutions, since room 5 is also connected to the entrance. So we need a condition to fix this. Go back to our Creation and add: VbotSol=1..2 Let's say that this means that if the number is 1, then the correct solution is from the right or left from the entrance, while if it's 2, the correct solution is from room 5 to the entrance. Since the path from room 5 might be already blocked though, we need to transform this code as well, just like we did with the other one. Loop VbotSol=1..2 If VbotSol=1, Break Loop ELSE If VmiddleBlock!=1, Break Loop And there we have it. If it's 1, then it means that we will solve it from the sides of the entrance, while if it's 2 we will check if the VmiddleBlock blocks the path from room 5 to the entrance. If it does, we will just randomize it again. Now, with this, we could just block the sides of the entrance accordingly. But we want a labyrinth, not a linear path. So, instead, we will block the paths of the rooms leading to the correct room, so that the player can go to them, but their path will be blocked. Let's start in this case. So, we said that when VbotSol is 2, the correct solution is through room 5. Now, if we are at room 6, everything is pretty much already blocked APART from the connection between rooms 5 and 4. Similarly, if we are at room 4, everything is blocked apart from the connection between rooms 5 and 6. So let's add these to our Rules: If VroomCurrent=5 AND VtopSol=1 AND VmiddleSol=1 AND VbotSol=2, switch RIGHT =true If VroomCurrent=5 AND VtopSol=2 AND VmiddleSol=1 AND VbotSol=2, switch LEFT =true Let's also add these to their adjacent rooms: If VroomCurrent=6 AND VtopSol=1 AND VmiddleSol=1 AND VbotSol=2, switch LEFT =true If VroomCurrent=4 AND VtopSol=2 AND VmiddleSol=1 AND VbotSol=2, switch RIGHT =true Now the only thing that's left (and i swear we're done), is to add the rules for VbotSol=1. This means the correct solution is from a side to the entrance. This means we will also block room 5. Let's do that: If VroomCurrent=5 AND VbotSol=1, switch DOWN =true and its adjacent room: If VroomCurrent=2 AND VbotSol=1, switch UP =true and now look at your paper. We're done! With these rules every other possible solution has already been blocked, leaving only 1 valid solution to our labyrinth, while still retaining many possible paths to the exit. Now, although solving it from the exit is absolutely linear, solving it from the entrance is not. And that's exactly what we wanted! In this manner, you will always have a brand new labyrinth each time the player re-enters it. 12. Cleaning our code Our code right now probably looks like Frankenstein's monster. I could just post my code directly, but i wanted you to follow my logic, rather than just copy and paste it. Anyway, our code must be cleaned now but that's the simplest part. Go to your "Rules" and see which commands can be grouped together. For example, we don't need 1000 "If VroomCurrent=5", we can just have one. So yeah, group everything up so it looks neat and feel free to experiment. Some Notes So what can you do now? Well, experiment with maps! For my labyrinth i created a dozen different maps with weird exits, and, in my Creation, i assigned a random map to a random room number. This means that not only will the labyrinth's solution be always different, but also the actual maps that the player traverses. I might try and make a more advanced guide that lets you randomize every single thing (including size and shape) but i have no idea if and when i will have that finished. Simple Labyrinths: A very simple version of this would be to only allow one path in Vexit and one path from Ventrance and have a condition to block a straight line and change it, if that's the case. Shape of the labyrinth: When we are talking about the shape of the labyrinth, we are not talking about different numbering of the rooms. The rooms will always form a box and will always be numbered as in this example. The difference will be that the rules will add blocks to completely remove rooms from the possible solutions. This is so that we don't have to change the code when the player goes left, right, up or down every time for every different shape. Solution automation: There is surely a way to automate possible solutions. This was just an example. Hell, there should be a way to automate solutions for any labyrinth size. A simple logic would be to block 2 random paths in Vexit, block 2 random paths in Ventrance, and, if the size of the labyrinth is larger than this example, have a program randomly selecting a valid path from the exit to the entrance and blocking all exits that it didn't go through. This would need a lot more rules and coding, and all possible combinations. Entrance/Exit Randomization: The way this example worked is that we kept the entrance and exit completely static. If you are a more advanced user you could surely randomize the entrance and exit, or even add more exits (leading outside the labyrinth but to a different map for example). This is why we added that VroomCurrent=Ventrance in our Creation. However, this would definitely need my previous point, to automate the solutions. It's certaintly not that hard, but it would need a lot of tinkering to make it work correctly every time. Size of the labyrinth: I would suggest not to change the size of the labyrinth, unless your entire game depends on it. A 3x3 box worked wonders for me. You can change the maps to be bigger or smaller, instead of changing the total number of rooms. In any case, if you really want to make it bigger, you just have to add more rules. The logic remains the same. Solve the labyrinth from the exit towards the entrance, and soon enough you will find your labyrinth ready. Switches, buttons, chests: You can randomize these things as well. Maybe the correct way is through room 9, but there is a gate there that needs a key, which you find in room 7. In my labyrinths i always have a bonus rule in my Rules, that is that if the correct way is room 9, then the button that opens it is in room 7, and vice versa. I also have possible rewards in rooms 1 and 3, if the correct solution is through room 5. Bosses, minibosses, easter eggs: You can pretty much go crazy with labyrinths. You can have some sort of contract to chase a criminal, instead of solving the labyrinth. Or you can have labyrinths that change their solutions each time you change rooms and hide an easter egg somewhere there. They're awesome! Typos: In case i made any typos, please do tell me. It's very frustrating to make typos when you're typing something as crucial as commands (even pseudo-commands as in this example), and it may end up not working just because i missed something. Still, the logic remains the same. Plugin Update: I have no idea when and if it will ever be ready. However, so far, i have managed to create a plugin that generates a labyrinth (only in code so far) with one possible solution, as long as the solution is never downwards. xD i know i know. It's super lame. Anyway, i am trying to get around the problems that occur when you attempt to allow the solution to be downwards. The cool thing is that the labyrinth has a random entrance and exit, and the user can input how big it is (for example, to test it i made a labyrinth 10x10 !!). However, even if it is completed, it will certainly require some work from the user. The user will still need to create the map(s) (like in step 1) and the events at the exits. The plugin will only generate the labyrinth, setup the rules, and then provide scriptcalls depending on where the player is going. Still better than nothing. I might attempt to make it work for a simple 3x3 labyrinth, since the rules there are much simpler, and avoid anything bigger for now.